How to find f ′ ′ ( x ) = csc x ?

Question

How to find       f    ′    ′          (      x      )        =          csc      x      ?

daneetuhxxtj · Accepted Answer

For             f              (        x        )              =          csc      x      , we have       f    ′          (      x      )        =    -          csc      x              cot      x        =    -          [              csc        x                    cot        x            ]      The product rule will be required to differentiate this.      f    ′    ′          (      x      )        =    -          [              (        -                  csc          x                          cot          x                )                    cot        x            +              (                  csc          x                )                    (        -                              csc            2                    x                )            ]            f    ′    ′          (      x      )        =          csc      x                      cot        2            x        +                  csc        3            x

How to find f ′ ′ ( x ) = csc x ?

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