Obtaining an expression for spontaneous magnetization in 1D Ising model with H=0 from the beginning

odenut6b

odenut6b

Answered question

2022-09-25

Obtaining an expression for spontaneous magnetization in 1D Ising model with H = 0 from the beginning

Answer & Explanation

Firetto8w

Firetto8w

Beginner2022-09-26Added 8 answers

You can just compute the expected value of M N = i = 1 N σ i with respect to the Gibbs measure:
M N N , T = i = 1 N σ i N , T ,
where N , T represents expectation with respect to the Gibbs measure for a system of N spins at temperature T (and H = 0).
Of course, if one uses free or periodic boundary condition, then the expectation is 0, at all temperatures, by symmetry. In order to get something nontrivial, let us assume + boundary condition (that is, assume that the first and last spins interact each with a boundary spin with fixed value 1).
The expectation of σ i can be computed easily either through the transfer matrix, or using a high-temperature expansion. The latter is shorter, since only two graphs contribute to both the numerators and the denominator: setting x = tanh ( J / k T )
σ i N , T = x i + x N + 1 i 1 + x N + 1 .
Therefore,
M N N , T = 2 x N + 1 x x N + 2 x N + 1 + x 1 .
In particular,
lim T 0 1 N M N N , T = 1.

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