A batch of 500 containers for frozen orange juice contains five that are defective. Two are selected at random without replacement from the batch. What is the probability that the second one selected is defective given that the first one is defective?

Bulldog The grt

Bulldog The grt

Answered question

2022-07-28

1.     A batch of 500 containers for frozen orange juice contains five that are defective. Two are selected at random without replacement from the batch.

a)    What is the probability that the second one selected is defective given that the first one is defective?

What is the probability that both are defective

Answer & Explanation

Jeffrey Jordon

Jeffrey Jordon

Expert2022-11-08Added 2605 answers

Given:

N=500 - the number of containers of orange juice in the batch

n=5 - the number of defective containers of orange juice in the batch

Consider events:

A - first container drawn at random from the batch is defective

B - second container drawn at random from the batch is defective

The drawing is done without replacement of the container drawn first.

Since the drawing is at random

P(x)=No. of possible outcomesNo. of outcomes in X​​​

a) P(BA)

This is the probability that one of the 4 defective containers is selected from the 499 remaining after the first defective one is drawn:

P(BA)=4499

b) P(AB)

The answer in (b) used the assumption of random choosing of the second chip.

However, by definition:

P(BA)=P(A)P(AB)

Using (1) we calculate P(A)=5500=1100

Multiplying (2) by P(A) and then substituting result of (a):

P(AB)=P(A)P(BA)=11004499=112475
 

The probability that both containers are defective is the probability that the first is the defective multiplied by the probability that the second one is defective given that the first was.

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