Recent questions in Force, Motion and Energy

Secondary
Answered

agrejas0hxpx
2022-05-10

Two objects, with masses ${m}_{1}$ and ${m}_{2}$, attract each other with force $F$. If the mass of ${m}_{1}$ increased by a factor of two then the new gravitational force would be:

F/4

2 F

4 F

F/2

Acceleration Due to Gravity
Answered

Azzalictpdv
2022-05-10

I'm far from being a physics expert and figured this would be a good place to ask a beginner question that has been confusing me for some time.

According to Galileo, two bodies of different masses, dropped from the same height, will touch the floor at the same time in the absence of air resistance.

BUT Newton's second law states that $a=F/m$, with $a$ the acceleration of a particle, $m$ its mass and $F$ the sum of forces applied to it.

I understand that acceleration represents a variation of velocity and velocity represents a variation of position. I don't comprehend why the mass, which is seemingly affecting the acceleration, does not affect the "time of impact".

Can someone explain this to me? I feel pretty dumb right now :)

Acceleration Due to Gravity
Answered

ureji1c8r1
2022-05-09

Is the gravitational acceleration we consider only the attraction due to the Earth's gravity or is it that of gravity plus the attraction due to Earth spinning?

We know that earth produces an acceleration towards the centre on any body near it due to gravitational attraction.

We denote this acceleration as $g$

But we also know that any body on Earth is also undergoing rotational motion due to earth's Spin. So every body should experience an outward centrifugal acceleration.

Does acceleration due to gravity $g$ take the centrifugal acceleration into consideration?

Gravitational force
Answered

enclinesbnnbk
2022-05-09

Gravitational force
Answered

rockandriot0odjn
2022-05-09

2. And is the Newtonian formula of gravitational force applicable for very small particles like electrons and protons etc.? From Formula of Gravitational Force, I'm referring to:

${F}_{G}=\frac{{\textstyle GMm}}{{\textstyle {R}^{2}}},$

where M and m are the masses of objects.

A logical explanation will be much appreciated.

Gravitational force
Answered

Blaine Stein
2022-05-09

Gravitational force
Answered

Jaime Coleman
2022-05-09

Gravitational force
Answered

oglasnak9h01
2022-05-09

$F=GMm/{r}^{2}$

Putting 0 in one of the two bodies' masses, gives no gravitational force. But light cannot escape from black hole due to its strong gravity, does that mean that light has mass? please correct me.

Gravitational force
Answered

kwisangqaquqw3
2022-05-09

Acceleration Due to Gravity
Answered

Paul Duran
2022-05-09

Is time dilation due to relative velocity and relative gravitational strength equivalent? That is, similar to Einstein's thought experiment where an observer in an enclosed capsule with no windows cannot tell the difference between acceleration due to gravity or due to some applied force, is there any observable difference between time dilation due to velocity versus that due to gravity?

Acceleration Due to Gravity
Answered

Jayla Faulkner
2022-05-09

Given any Angle -> 0-90

Given any Initial Velocity -> 1-100

Given Acceleration due to Gravity -> 9.8

Plot every x,y coordinate (the parabolic trajectory) with cartesian coordinates and screen pixels (not time)

This should only be one equation as far as I can tell, a "y=" type equation, telling you the height in y coordinates based on the current x coordinate which is increasing by 1 as you plot across a computer screen.

I've come up with an equation that works for the angle 45, but doesn't seem to be entirely accurate for any other angle, I suspect it has something to do with the angle 45 having 1 solution and every other angle having 2 solutions (two different initial velocities land on the same spot), but I'm stumped beyond that.

$y={y}_{0}-(x-{x}_{0})\cdot \mathrm{tan}\frac{\frac{1}{2}\cdot \frac{9.8}{{v}_{0}^{2}}\cdot x-{x}_{0}^{2}}{\mathrm{cos}{\theta}^{2}}$

Acceleration Due to Gravity
Answered

Peia6tvsr
2022-05-08

The period of a pendulum is given by

$T=2\pi \sqrt{\frac{L}{g}}.$

If we take a pendulum where there is no gravitational field, then $g=0$, therefore the period should become infinity. In such a condition what will our time relative to that of a person on earth will be? I believe that the time of a person will become too slow as it takes infinite time to complete one oscillation. Please tell me whether I am right or wrong, and if I am wrong please help me understand why.

Gravitational force
Answered

poklanima5lqp3
2022-05-08

Gravitational force
Answered

Edith Mayer
2022-05-08

Gravitational force
Answered

Landon Mckinney
2022-05-08

Gravitational force
Answered

Azzalictpdv
2022-05-08

Acceleration Due to Gravity
Answered

Marissa Singh
2022-05-08

Why is the acceleration due to gravity at the center of the earth $0$?

My Attempt

actually at the center distance from the surface is equal to the radius so the formula

${g}^{\prime}=(1-\frac{d}{R})\times g$

yields $0$.

But can anyone give me the other reason for this?

Acceleration Due to Gravity
Answered

Azzalictpdv
2022-05-08

Does acceleration due to gravity increase when an object at a said radius is doubled? Like for instance, if I said the radius of the earth is $5\phantom{\rule{thinmathspace}{0ex}}\mathrm{k}\mathrm{m}$ (not to scale obviously) if I doubled that, so $10\phantom{\rule{thinmathspace}{0ex}}\mathrm{k}\mathrm{m}$ will acceleration due to gravity double? Or maybe $g/2$? Or would the acceleration stay the same no matter distance?

Acceleration Due to Gravity
Answered

Aedan Tyler
2022-05-08

I need some help with below. So according to Newton's 2nd law, $a=F/m$, for a given mass, the acceleration depends on mass.

But acceleration due to gravity is independent of mass. There seems some contradiction; I am sure I am missing something, but I can't pin-point what that is.

When you have to provide correct answers to the questions based on motion equations physics, you must start with the examples that can help you learn more about the theory and see relevant examples. If you find it too challenging, start with the equations that help to determine the force of the motion as you estimate the energy that is being produced. It’s also helpful to compare several lab experiments to see the differences in how the concepts operate. Such an approach will help you to see the example of force and explain it both verbally and with the formulas.