f(t)=sin(2t)
I calculated as , but the answer is . What went wrong?
I calculated the exact value of as follows:
The actual answer is
(ad≥ + 2ycost = coser?t
CA⃡ is the perpendicular bisector of̅BD̅̅̅̅.
Given that AB=3x and AD=4x-1, then what
is the value of x and the hypotenuse?
sinh(x-y)=Sinhx*coshy-sinhy**coshx
Let
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