"A survey shows that 63% of kids like brand A shoes and 76% like brand B shoes. brand B. Each boy in the group surveyed expresses at least one preference. Calculate the percentage of the boys who like both brand A and B and the percentage of those who like only the A. My attemps: I have thought that the total number nb of boys cannot obviously exceed 100%; but I have instead |AcupB|=63%+76%=139% Subtracting the percentage of boys who like both brand A and B that is 100% I will have the percentage n′: n′=139%−100%=39% After the percentage of those who like only the A is: |A−B|=|A|−|AcapB|=63%−39%=24% Question: I have used the logic: surely the percentage of kids can't be more than 100%. Is there another motivation or is that the only one?"

Addison Parker

Addison Parker

Answered question

2022-09-10

A survey shows that 63% of kids like brand A shoes and 76% like brand B shoes. brand B. Each boy in the group surveyed expresses at least one preference. Calculate the percentage of the boys who like both brand A and B and the percentage of those who like only the A.
My attemps: I have thought that the total number nb of boys cannot obviously exceed 100%; but I have instead
| A B | = 63 % + 76 % = 139 %
Subtracting the percentage of boys who like both brand A and B that is 100% I will have the percentage n′:
n = 139 % 100 % = 39 %
After the percentage of those who like only the A is:
| A B | = | A | | A B | = 63 % 39 % = 24 %
Question: I have used the logic: surely the percentage of kids can't be more than 100%. Is there another motivation or is that the only one?

Answer & Explanation

Ashlynn Cox

Ashlynn Cox

Beginner2022-09-11Added 12 answers

You have
| A B | 100 % ,
since everyone must choose at least one option. The left-hand side equals
| A | + | B | | A B | .
Isolating | A B | then yields
| A B | = | A | + | B | | A B | ,
so
| A B | 63 % + 76 % 100 % = 39 % .
The way you computed |A| is fine.

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