Knowing that (a_i)_(i>=1) prove that forall_n in NN: sum_(i=1)^n ra_i=r(sum_(i=1)^n a_i)

Jonas Huff

Jonas Huff

Answered question

2022-11-19

Knowing that ( a i ) i 1 prove that n N
i = 1 n r a i = r ( i = 1 n a i )

Answer & Explanation

Laura Fletcher

Laura Fletcher

Beginner2022-11-20Added 22 answers

Base of induction: consider the case n=1. The statement takes the form r a 1 = r a 1 , obviously true.
Suppose the statement was proved for n-1 terms: that is, we know that
i = 1 n 1 r a i = r ( i = 1 n 1 a i )
Add r a n to both sides:
i = 1 n 1 r a i + r a n = r ( i = 1 n 1 a i ) + r a n
Use the distributive property of multiplication:
i = 1 n 1 r a i + r a n = r ( i = 1 n 1 a i + a n )
Finally, absorb the additional term into the Σ notation for the sum:
i = 1 n r a i = r ( i = 1 n a i )

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