Suppose I have matrix A and vectors B and C. I assume two facts about these matrices: (1) Assume that AB=AC for rectangular matrix A in RR^(a xx b) with rank r where 0<r<min(a,b). (2) Assume that (I_b-A′(AA′)^(-)A)C=0 where (AA′)^(-) is the pseudo-inverse of AA′. Do (1) and (2) together imply that (I-A′(A′A)^(-)A)B=0?

Keshawn Moran

Keshawn Moran

Answered question

2022-11-13

Suppose I have matrix A and vectors B and C. I assume two facts about these matrices:
(1) Assume that A B = A C for rectangular matrix A R a × b with rank r where 0 < r < min ( a , b )
(2) Assume that ( I b A ( A A ) A ) C = 0 where ( A A ) is the pseudo-inverse of A A
Do (1) and (2) together imply that ( I A ( A A ) A ) B = 0?

Answer & Explanation

Brooklyn Mcintyre

Brooklyn Mcintyre

Beginner2022-11-14Added 18 answers

Consider the conditions and equations columnwise. Let b and c be the j-th columns of B and C respectively. Since I A T ( A A T ) 1 A is the orthogonal projection onto ker ( A ), you are essentially asking whether b ker ( A ) when b c ker ( A ) and c ker ( A ) , i.e. whether ker ( A ) + ker ( A ) ker ( A ) . As ker ( A ) 0, the answer is clearly negative.
More concretely, pick any nonzero vector v ker ( A ). Let B = C + v u T where u 0 is an arbitrary. Then AB=AC and ( I A T ( A A T ) 1 ) B = ( I A T ( A A T ) 1 A ) v u T = v u T 0

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