An urn contains five red R balls numbered 1, 2, 3, 4, and 5, four white W balls numbered 6, 7, 8, and 9, and four black B balls numbered 10, 11, 12, and 13. A ball is drawn from the urn. What is the probability that it is red or odd-numbered O?

Cyrus Travis

Cyrus Travis

Answered question

2022-10-27

An urn contains five red R balls numbered 1, 2, 3, 4, and 5, four white W balls numbered 6, 7, 8, and 9, and four black B balls numbered 10, 11, 12, and 13. A ball is drawn from the urn. What is the probability that it is red or odd-numbered O?

Answer & Explanation

lefeuilleton42

lefeuilleton42

Beginner2022-10-28Added 12 answers

Given:
In an urn 5  red balls  1 , 2 , 3 , 4 , 5 4  white balls  6 , 7 , 8 , 9 4  black balls  10 , 11 , 12 , 13
Total number of balls =13
let, P(R) = probability of drawing a red ball
P(0)=probability of drawing an add-numbered ball.
Now in a total of 13 balls, there are 5 red balls
P ( R ) = 5 13
There are 7 odd numbered balls in total 13 balls
1,3,5 - Red - 3 odd
7,9 - white - 2 odd
11,13 - black - 2 odd
Total 7 odd
and there are 3 add and red balls
P ( R 0 ) = P ( R ) + P ( 0 ) P ( R 0 ) = 5 13 + 7 13 3 13 = 9 13 = 0.69
Probability that ball is red or odd-number
= 9 13 = 0.69

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