When is f(k):=8k^2+8k+1 a square for k in Z>=0?

George Morales

George Morales

Answered question

2022-10-24

When is f ( k ) := 8 k 2 + 8 k + 1 a square for k Z 0 ?

Answer & Explanation

hanfydded1c

hanfydded1c

Beginner2022-10-25Added 17 answers

y 2 = 8 k 2 + 8 k + 1 = 2 ( 2 k + 1 ) 2 1 = 2 x 2 1 is (more-or-less) a Pell's equation, concerning which there is a large and readily-available literature. One solution is x = y = 1. If you let ( 1 + 2 ) n = y n + x n 2 for n odd, then you'll have y n 2 2 x n 2 = 1, and in fact all solutions arise this way.

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