Show that if lim_(x->a) f(x)=L, then lim_(x->a) cos(f(x))=cos(L).

gaby131o

gaby131o

Answered question

2022-09-26

Show that if lim x a f ( x ) = L, then lim x a c o s ( f ( x ) ) = c o s ( L ).

Answer & Explanation

Mackenzie Lutz

Mackenzie Lutz

Beginner2022-09-27Added 13 answers

cos ( A ) cos ( B ) = 2 sin ( A + B 2 ) sin ( A B 2 )
Apply this with A = f ( x ) and B = LL. Then
| cos ( f ( x ) ) cos ( L ) | = 2 | sin ( f ( x ) + L 2 ) sin ( f ( x ) L 2 ) | .
Now, recall that | sin ( t ) | | t | , so,
| cos ( f ( x ) ) cos ( L ) | 1 2 | f ( x ) + L | | f ( x ) L | .
And from here, it is easy to conclude a δ ε type proof.
Ivan Buckley

Ivan Buckley

Beginner2022-09-28Added 4 answers

For the sake of completeness,
cos ( a + b ) = cos ( a ) cos ( b ) sin ( a ) sin ( b )
cos ( a b ) = cos ( a ) cos ( b ) + sin ( a ) sin ( b )
by substracting
cos ( a + b ) cos ( a b ) = 2 sin ( a ) sin ( b ) .
Now, calling A = a + b and B = a b, gives a = A + B 2 and b = A B 2 .

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?