How can I prove that : 2 arctan &#x2061;<!-- ⁡ --> ( x ) + arcsin &#x2

Tristian Velazquez

Tristian Velazquez

Answered question

2022-06-22

How can I prove that :
2 arctan ( x ) + arcsin ( 2 x 1 + x 2 ) = π , x>1
What is the best way to do this ?

Answer & Explanation

upornompe

upornompe

Beginner2022-06-23Added 20 answers

An easy way is to differentiate the function
f ( x ) = 2 arctan ( x ) + arcsin ( 2 x 1 + x 2 )
and show that f′(x)=0 so that f is a constant. Then calculate the constant by letting x be a well-chosen number.
deceptie3j

deceptie3j

Beginner2022-06-24Added 8 answers

You can prove it without differentiating: set t = 2 arctan x. This means
tan t 2 = x and π < t < π .
Furthermore, as x>1, we have π 2 < t < π
Now, by the half-angle formulae (actually this is where the formula we seek to prove comes from),
sin t = 2 x 1 + x 2 , whence t { arcsin 2 x 1 + x 2 or π arcsin 2 x 1 + x 2 mod 2 π .
Knowing π 2 < t < π, we necessarily have
t = 2 arctan x = π arcsin 2 x 1 + x 2 .

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