If there are 20 people with 17 men and 3 women and they seat themselves...

Formulate the question this way: there are 20 people in a room, 17M and 3W. there's a table with 5 seats, what is the probability that only men sit in this table?
Part 1: the universe:
How many combination of 5 can you form from 20? Answer ${\displaystyle (\genfrac{}{}{0ex}{}{20}{5})}$
Part 2: your request:
You request to know how many M only can be seated in this table? Answer ${\displaystyle (\genfrac{}{}{0ex}{}{17}{5})}$
Part 3: Result
so the answer is:
$\frac{(\genfrac{}{}{0ex}{}{17}{5})}{(\genfrac{}{}{0ex}{}{20}{5})}$