Mara Cook

2022-06-15

The number of ways in which $mn$ different items can be divided equally int $m$ groups, each containing $n$ objects and the order of the groups is important,is: $\frac{(mn)!}{(n!{)}^{m}}\frac{1}{m!}\ast (m!)$

Layla Love

Beginner2022-06-16Added 29 answers

Try to adapt the explanation above to see how to obtain this formula; note that a simpler way of writing it is just as $\frac{(mn)!}{(n!{)}^{m}}$, since the two $m!$ will cancel out.