Finding real roots of P(x)=x8−x7+x2−x+15

Abbey Ellison

Abbey Ellison

Answered

2022-04-05

Finding real roots of P(x)=x8x7+x2x+15

Answer & Explanation

tralhavahr9c

tralhavahr9c

Expert

2022-04-06Added 16 answers

we have to calculate no. of ral roots of x8x7+x2x+15=0
Solution: Let f(x)=x8x7+x2x+15, we check real solution in xR
If x0, then f(x)=x8x7+x2x+15>0
If 0<x<1, then f(x)=x8+x2(1x5)+(1x)+14>0
If x1, Then f(x)=x7(x1)+x(x1)+15>0
So we observe that f(x)=x8x7+x2x+15>0;xR
So f(x)=x8x7+x2x+1=0 has no real roots for all xR

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get your answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?