Prove that \(\displaystyle{16}{{\cos}^{{5}}{A}}-{20}{{\cos}^{{3}}{A}}+{5}{\cos{{A}}}={\cos{{5}}}{A}\)

Asher Olsen

Asher Olsen

Answered question

2022-04-01

Prove that
16cos5A20cos3A+5cosA=cos5A

Answer & Explanation

Charlie Haley

Charlie Haley

Beginner2022-04-02Added 14 answers

Use
2cosx=eix+eix
Then
32cos5x=e5ix+5e3ix+10eix+5e3ix+e5ix
=2cos5x+10cos3x+20cosx
Moreover
8cos3x=e3ix+3eix+3eix+e3ix=2cos3x+6cosx
Therefore
16cos5x20cos3x+5cosx=(cos5x+5cos3x+10cosx)5(cos3x+3cosx)+5cosx=cos5x
This is actually backwards, so here's a different proof:
cos5x+isin5x=(cosx+isinx)5
=cos5x+5icos4xsinx10cos3xsin2x10icos2xsin3x+5cosxsin4x+isin5x
Taking the real part
cos5x=cos5x10cos3x(1cos2x)+5cosx(1cos2x)2
and you can finish.

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