How do I go about simplifying \(\displaystyle{1}-{\frac{{{{\sin}^{{2}}{x}}{\tan{{x}}}}}{{{\tan{{x}}}+{1}}}}-{\frac{{{{\cos}^{{2}}{x}}}}{{{\tan{{x}}}+{1}}}}\)

xxgetthisar08

xxgetthisar08

Answered question

2022-03-27

How do I go about simplifying 1sin2xtanxtanx+1cos2xtanx+1 to sinxcosx

Answer & Explanation

SofZookywookeoybd

SofZookywookeoybd

Beginner2022-03-28Added 15 answers

We have
1sin2xtanxtanx+1cos2xtanx+1

 

=1sin2xtanx+cos2xtanx+1

 

=1sin3x+cos3xsinx+cosx

 

=sinx(1sin2x)+cosx(1cos2x)sinx+cosx

 

=sinxcos2x+cosxsin2xsinx+cosx

 

=sinxcosx

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?