Which is the easiest way to evaluate: \int_0^{\pi/2}(\sqrt{\tan x}+\sqrt{\cot x})

Tagiuraoob

Tagiuraoob

Answered question

2022-02-26

Which is the easiest way to evaluate:
0π2(tanx+cotx)

Answer & Explanation

faraidz3i

faraidz3i

Beginner2022-02-27Added 10 answers

0π2tanxdx+cotxdx
=0π2sinx+cosxsinxcosxdx=0π2sinx+cosx2sinxcosx2dx=2
0π2sinx+cosx1(12sinxcosx)dx
Let t=sinxcosx, dx=dtsinx+cosx
xπ2t=(sinxcosx)1
x0t=(sinxcosx)1
21111t2dt=2[sin1t]11=2[π2(π2)]=2π

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?