absolutestylehc

2022-02-02

How do you find the product of the complex number and its conjugate of $-7+\sqrt{13i}$ ?

Devyn Figueroa

Beginner2022-02-03Added 10 answers

Step 1

The given complex number is$-7+i\sqrt{13}$

The conjugate of the given number is$-7-i\sqrt{13}$

The product:

$=(-7+i\sqrt{13})(-7-i\sqrt{13})={(-7)}^{2}-{\left(i\sqrt{13}\right)}^{2}$

$=49-13{i}^{2}=49-(-13)$

$=49+13=62$

The given complex number is

The conjugate of the given number is

The product: