What is the square root of 2i?

treslagosnv

treslagosnv

Answered question

2022-02-01

What is the square root of 2i?

Answer & Explanation

euromillionsna

euromillionsna

Beginner2022-02-02Added 16 answers

Step 1
2i={1+i, 1i}
Let us look at some details.
Let z=2i
(Note that z are complex numbers.)
by squaring.
z2=2i
by using the exponential form z=reiθ
r2ei(2θ)=2i=2ei(π2+2nπ)
{r2=2r=22θ=π2+2nπθ=π4+nπ
So, z=2ei(π4+nπ)
by Eular's Formula: eiθ=cosθ+isinθ
z=2[cos(π4+nπ)+isin(π4+nπ)]
=2(±12±12i)=±1±i
I kept the following original post just in case someone needs it.
(2i)12=(2)12(i)12
(i)12=1
(2i)12=(2)12×1
(2)12=1.41
(2i)12=1.41×1=1.41

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?