How to find Re: z, when z=i^{i+1}?

Gabriela Duarte

Gabriela Duarte

Answered question

2022-01-31

How to find Re: z, when z=ii+1?

Answer & Explanation

terorimaox

terorimaox

Beginner2022-02-01Added 16 answers

Step 1
Note that i=eπ2i
Hence:
ii+1=ii×i1=(eπ2i)i×i=e(π2i)i×i=rπ2×i
which is pure imaginary.
So:
Re(ii+1)=0

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