How do you solve 2x^{4}-128=0?

Ahmed Stewart

Ahmed Stewart

Answered question

2022-02-01

How do you solve 2x4128=0?

Answer & Explanation

Telering3b

Telering3b

Beginner2022-02-02Added 11 answers

Step 1
The difference of squares identity can be written:
a2b2=(ab)(a+b)
So we find:
0=2x4128
=2(x464)
=2((x2)282)
=2(x28)(x2+8)
=2(x2(22)2)(x2(22i)2)
=2(x22)(x+22)(x22i)(x+22i)
So the roots of the quartic equation are:
±22 and ±22i

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