How do you express the complex number in trigonometric form: 1−(3)i?

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Kudusind · Accepted Answer

to convert to trigonometric form that is r(cos⁡θ+isin⁡θ) where  - r=x2+y2  - θ=tan−1(yx)−π&amp;lt;θ≤π  Here x=1and y=−3  ⇒r=12+(−3)2=2  θ=tan−1(−3)=−π3  ⇒2(cos⁡(−π3)+isin⁡(−π3))  =2(cos⁡(π3)−isin⁡(π3))  ⇒1−3i=2(cos⁡(π3)−isin⁡(π3))

How do you express the complex number in trigonometric form: 1−(3)i?

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