Evaluating \lim_{x\to0} \frac{\cos x - \cos 3x}{\sin 3x^2 - \sin

Gerald Ritter

Gerald Ritter

Answered question

2022-01-30

Evaluating limx0cosxcos3xsin3x2sinx2
Is there a simple way of finding the limit?
I know the long one: rewrite it as
limx0cosxcos(3x)sin(3x2)11sin(3x2)sin(x2)
and then find both limits in separately applying LHospitals rule several times. The answer is 2

Answer & Explanation

coolbananas03ok

coolbananas03ok

Beginner2022-01-31Added 20 answers

By standard limits
sinxx1
1cosxx212
we have that
cosxcos(3x)sin(3x2)sin(x2)=cosx1+1cos(3x)x2sin(3x2)sin(x2)x2=1cosxx2+91cos(3x)(3x)23sin(3x2)3x2sin(x2)x212+9231=2
Howard Gallagher

Howard Gallagher

Beginner2022-02-01Added 13 answers

Hint: Use
sin3a=3sina4sin3a
cos3a=4cos3a3cosa
Edit: After substutution it is
limx02cosxsin2xsinx2cos2x2=2

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