Get the solution to "Find the general solution (i) cot⁡θ=−d13 (ii) 4cos2θ=1" - Plainmath

bistandsq

Answered question

2022-01-30

Find the general solution (i)

\cot θ = - d \frac{1}{\sqrt{3}}

(ii)

4 \cos^{2} θ = 1

Answer & Explanation

primenamaqm

Beginner2022-01-31Added 12 answers

We know that

\cot (- \frac{π}{3}) = - \frac{\sqrt{3}}{3}

and

\cot (θ + π) = \cot θ

similarly

\cos (\frac{π}{3}) = \frac{1}{2}

and

\cos^{2} (θ + π) = \cos^{2} θ

therefore

(i) x = k π - \frac{π}{3}

(i i) x = k π \pm \frac{π}{3}

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