Strange trigonometric simplification? \cos^{-1}(-\frac{1}{3\sqrt{7}})-\frac{1}{2}\pi = \sin^{-1}\frac{1}{3\sqrt{7}}

Jamya Elliott

Jamya Elliott

Answered question

2022-01-28

Strange trigonometric simplification?
cos1(137)12π=sin1137

Answer & Explanation

becky4208fj

becky4208fj

Beginner2022-01-29Added 10 answers

In the first step
cos1(137)12π=(πcos1(137))12π
we are using that for 0xπ
arccos(θ)=πarccosθ
which is trivial from the definition of arccosθ dependin for the fact that cosθ=cos(θ)
For the second step note that for 0xπ2
θ=π2arccosxsinθ=sin(π2arccosx)=cos(arccosx)=x
therefore
θ=arcsinx

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