Find the roots (real or complex) of the equation 2a2(1+cos⁡x)−(1+a2+b2)2=0,a,b∈R ATTEMPT: Solving for x, we...

treetopssan

treetopssan

Answered

2022-01-30

Find the roots (real or complex) of the equation 2a2(1+cosx)(1+a2+b2)2=0,a,bR
ATTEMPT: Solving for x, we arrived with
x=arccos[(1+a2+b2)22a21]
However, I got stuck because of the required domain of arccos() which is [-1,1] while the expression (1+a2+b2)22a21 does not possibly be within this interval for arbitrary values of a and b. Sometimes I am tempted to say that no general solution exists even in C. Can anyone help me out?

Answer & Explanation

Brynn Ortiz

Brynn Ortiz

Expert

2022-01-31Added 12 answers

What you should know is arccosx, if the domain is [-1,1], it has real value, and if the domain isnt,

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get your answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?