Simplifying \frac{\cot(34^{\circ})\sin(44^{\circ})}{\sin(22^{\circ})\sin(56^{\circ})} We know that \cot \alpha = \frac{\sin \alpha }{\cos

trefoniu1

trefoniu1

Answered question

2022-01-29

Simplifying cot(34)sin(44)sin(22)sin(56)
We know that cotα=sinαcosα and sin(44)=2sin(22)cos(22)

Cancelling similar terms out
cot(34)2cos(22)sin(56)=cos(34)sin(34)2cos(22)sin(56)
Using the identity cos(90α)=sin(α)
sin(56)sin(34)2cos(22)sin(56)=2sin(56)cos(22)sin(34)sin(56)=2cos(22)sin(34)
Since the degrees aren't the same, I could not proceed further.

Answer & Explanation

marzembreax

marzembreax

Beginner2022-01-30Added 13 answers

2sin68sin34=4cos34

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