Prooving an upper bound for \sum_{k=0}^N \frac {k^2}{N^3} \cos (\frac{k}{N}x) im

plorinosakl

plorinosakl

Answered question

2022-01-29

Prooving an upper bound for k=0Nk2N3cos(kNx)
im struggling to proove, that there exsists an constant C, so that for every NN and every x[0,Nπ], the following holds:
k=0Nk2N3cos(kNx)C(x1+x2+x3)

Answer & Explanation

Micah May

Micah May

Beginner2022-01-30Added 11 answers

Let us consider f(y)=y2cos(xy). Then
01f(y),dy=2xcos(x)+(x22)sin(x)x3ll2(1x+1x2+1x3)
and the difference between this integral and the associated Riemann sum
1Nk=0N(kN)2cos(xkN)
is bounded by xN2 due to the Lipschitz-continuity of cos and summation/integration by parts.
It follows that your bound holds as soon as N|x|

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