If \pi<\alpha<\frac{3\pi}{2} then the expression \sqrt{4\sin^4 \alpha+\sin^2 2\alpha}+4 \cos^2 (\frac{\pi}{4}-\frac{\alpha}{2})

Aubrey Hendricks

Aubrey Hendricks

Answered question

2022-01-25

If π<α<3π2 then the expression 4sin4α+sin22α+4cos2(π4α2)

Answer & Explanation

rakije2v

rakije2v

Beginner2022-01-26Added 12 answers

We note that in π<α<3π2, the value of sinα is negative.
Now,
4sin4α+sin22α
=4sin2α[sin2α+cos2α]
=|2sinα|=2sinα
Now, you have correctly simplified the value of 4cos2(π4α2) as 2+2sinα
As a result, the answer must simply be 2

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