Solve equation 1+\sin^2 \theta=3\sin \theta \cos \theta (\text{ given }

treetopssan

treetopssan

Answered question

2022-01-25

Solve equation 1+sin2θ=3sinθcosθ(  given  tan7134=3)

Answer & Explanation

Prince Huang

Prince Huang

Beginner2022-01-26Added 15 answers

12sinθcosθ+sin2θsinθcosθ=0
(sinθcosθ)2+sinθ(sinθcosθ)=0
(sinθcosθ)(2sinθcosθ)=0
tanθ=1  or  tanθ=12
θ=nπ+π4
tainiaadjouctlw

tainiaadjouctlw

Beginner2022-01-27Added 14 answers

Use 3=1+121112=tan(45+θ)

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