Answered: "Simplifying cos2x−sin2xsin⁡2x" - Plainmath

Oberlaudacu

Answered question

2022-01-15

Simplifying

\frac{\cos^{2} x - \sin^{2} x}{\sin 2 x}

Answer & Explanation

Edward Patten

Beginner2022-01-16Added 38 answers

\cos^{2} x - \sin^{2} x = \cos (2 x)

. So the result can be written as

\cot (2 x)

sonSnubsreose6v

Beginner2022-01-17Added 21 answers

Continue with

\frac{\cos x}{2 \sin x} - \frac{\sin x}{2 \cos x} = \frac{1}{2 \tan x} - \frac{12}{\tan x} = \frac{1 - \tan^{2} x}{2 \tan x} = \frac{1}{\tan 2 x}

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