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2022-01-19Added 437 answers
We can notice that
I am going to prove that
if π2<α+β<3π2 then α+β=π+tan−1(tanα+tanβ1−tanα⋅tanβ)
As |α+β−π|<π2 and the function tangent is invertible in [−π2,π2] it follows that
α+β−π=tan−1(tanα+tanβ1−tanα⋅tanβ) , therefore:
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