please solve this question as soon as possible

Answered

2022-01-04

please solve this question as soon as possible 

Answer & Explanation

alenahelenash

alenahelenash

Expert

2022-02-10Added 366 answers

a) Let the equation be of form,

a(x3)+b(y0)+c(z(1))=0

Since it through (2,2,3) and (7,1,4)

a(23)+b(2)+c(3+1)=0

5a+2b3c=0 --- (1)

a(73)+b(10)+c(4+1)=0

4a+b3c=0

5a+2b3c=0

a3+6=b15+12=c85

a3=b3=c3

3(x3)3(y)+3(2+1)=0

xy+z=2 Required plane

b) Since the given line is intersetting with the plane for t=1, hence distance =0

c) Angle,

θ=cos1(<7,2,1><1,1,1>72+22+1212+12+12)

=cos1(6543)

=cos1(692)

=cos1(23)

d) Since normal of plane will be direction ratio for line,

x=6+t,y=2t,z=8+t

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