fanyattehedzg

2021-12-20

Factor ${x}^{3}+1$.

habbocowji

Expert

We have the formula:
${a}^{3}+{b}^{3}=\left(a+b\right)\left({a}^{2}-ab+{b}^{2}\right)$
Thus, we have
${x}^{3}+{1}^{3}=\left(x+1\right)\left({x}^{2}-x×1+{1}^{2}\right)=\left(x+1\right)\left({x}^{2}-x+1\right)$

Heather Fulton

Expert

${x}^{3}+{1}^{3}=\left(x+1\right)\left({x}^{2}-x+1\right)$ with the help of the Sum of Cubes Identity.

RizerMix

Expert

Apply the Sum of Cubes Formula ${a}^{3}+{b}^{3}=\left(a+b\right)\left({a}^{2}-ab+{b}^{2}\right)$ and you get
${x}^{3}+{1}^{3}=\left(x+1\right)\left({x}^{2}-x+1\right)$

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