Find the values of m and k so that [1−2m3]⋅[k02−134]=[3−6−6−1916]

Question

Find the values of m and k so that  [1−2m3]⋅[k02−134]=[3−6−6−1916]

Anonym · Accepted Answer

Step 1  According to the given information, it is required to determine the values of m and n. [1−2m3]⋅[k02−134]=[3−6−6−1916]  Step 2  First multiply the matrices.  [1−2m3]⋅[k02−134]=[1(k)+(−2)(−1)1(0)+(−2)(3)1(2)+(−2)(4)mk−30+3(3)2m+12]  [1−2m3]⋅[k02−134]=[k+2−6−6mk−392m+12]  Step 3  Two matrices are equal if their corresponding entries are equal.  A=B⇒aij=bij  [k+2−6−6mk−392m+12]=[3−6−6−1916]  so,  k+2=3  k=1  2m+12=16  2m=4  m=2

Jeffrey Jordon · Accepted Answer

Answer is given below (on video)

Jeffrey Jordon · Accepted Answer

Answer is given below (on video)

Find the values of m and k so that [1−2m3]⋅[k02−134]=[3−6−6−1916]

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