Physics

Answered question

2021-10-25

A dog in an open field runs 12.0 m east and then 28.0 m in a direction 50.0° west of north. In what direction and how far must the dog then run to end up 10.0 m south of her original starting point?

Answer & Explanation

Jeffrey Jordon

Jeffrey Jordon

Expert2021-10-25Added 2605 answers

image

R=A+B+C

C=RAB

Adding components un x-axis: Cx=RxAxBx=0A(Bsin50)

Cx=012+28sin50=9.4492 m

Adding components un y-axis: Cy=RyAyBy=R0Bcos50

Cy=100(28)cos50=27.9981 m

C=(9.4492)2+(27.9981)2=29.6 m

α=tan1(9.449227.9981)=18.6 East of South

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