How many permutations of three items can be selected from a group of six? Use the letters A, B, C, D, E, and F to identify the items, and list each of the permutations of items B, D, and F.

Marvin Mccormick

Marvin Mccormick

Answered question

2021-05-17

How many combinations of three items out of a group of six can be chosen? List all of the combinations of objects B, D, and F after identifying them with the letters A, B, C, D, E, and F.

Answer & Explanation

oppturf

oppturf

Skilled2021-05-18Added 94 answers

Permutation definition (order matters):
Pn,r=n!(nr)! 
Combination definition (order is not crucial):
Cn,r=n!r!(nr)! 
with n!=n(n1)...21 
Given: 
n=6 
r=3 
P6,3=6!(63)!=6!3!3!=65...1321=654=120 
All the methods that we can choose three results from the set of three items (B,D, and F): 
BBB, BBD, BDB, DBB, BBF, BFB, FBB, BDF, BFD, DDD, DDB, DBD, BDD, DDF, DFD, FDD, DBF, DFB, FFF, FFB, FBF, BFF, FFD, FDF, DFF, FBD, FDB

xleb123

xleb123

Skilled2023-06-11Added 181 answers

To calculate the number of combinations of three items chosen from a group of six, we can use the formula for combinations, which is given by:
C(n,k)=n!k!(nk)!
Here, n represents the total number of items in the group (6 in this case), and k represents the number of items to be chosen (3 in this case).
Substituting the values into the formula, we have:
C(6,3)=6!3!(63)!
Simplifying further:
C(6,3)=6!3!·3!
Since n!=n·(n1)·(n2)··2·1, we can calculate:
6!=6·5·4·3·2·1=720
Similarly, 3!=3·2·1=6
Substituting these values into the equation:
C(6,3)=7206·6
C(6,3)=72036
C(6,3)=20
Therefore, there are 20 different combinations of three items that can be chosen from a group of six.
Now, let's list all the combinations of objects B, D, and F, using the letters A, B, C, D, E, and F.
The possible combinations are:
1. A, B, D
2. A, B, F
3. A, C, D
4. A, C, F
5. A, D, E
6. A, D, F
7. B, C, D
8. B, C, F
9. B, D, E
10. B, D, F
11. C, D, E
12. C, D, F
13. C, E, F
14. D, E, F
These are the 14 combinations of objects B, D, and F when represented by the letters A, B, C, D, E, and F.
fudzisako

fudzisako

Skilled2023-06-11Added 105 answers

The number of combinations of three items chosen from a group of six can be calculated using the formula for combinations, which is given by (nk)=n!k!(nk)!, where n is the total number of items and k is the number of items chosen.
In this case, we have n=6 and k=3. Plugging these values into the formula, we get (63)=6!3!(63)!=6!3!3!=6×5×43×2×1=20.
Therefore, there are 20 combinations of three items that can be chosen from a group of six.
To list all of the combinations of objects B, D, and F, we can use the following combinations:
1. BDF
2. BFD
3. DBF
4. DFB
5. FBD
6. FDB
These are the six possible combinations of objects B, D, and F.

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