How to show that the point (7/25, 24/25) is on the unit circle?

The unit circle's center is located at (0,0). The point is on the unit circle if the distance between the center and the provided point turns out to be 1.
In this instance, the calculated distance of the provided position from (0,0) is
${\displaystyle \sqrt{{\left(\frac{7}{25}\right)}^2+{\left(\frac{24}{25}\right)}^2}}$
${\displaystyle \sqrt{\frac{49+576}{625}}}$
=1. Hence the proof.