Which polynomial function has x intercepts –1, 0, and 2 and passes through the point (1, –6)? f(x) = x^3 – x^2 – 2x f(x) = 3x^3 – 3x^2 – 6x f(x) = x^3 + x^2 – 2x f(x) = 3x^3 + 3x^2 – 6x

Adrianna Esparza

Adrianna Esparza

Answered question

2023-01-09

Which polynomial function has x intercepts –1, 0, and 2 and passes through the point (1, –6)?
f(x)=x3x22x
f(x)=3x33x26x
f(x)=x3+x22x
f(x)=3x3+3x26x

Answer & Explanation

Mikayla Cox

Mikayla Cox

Beginner2023-01-10Added 15 answers

A polynomial function with x-intercepts of 1, 0, and 2 has the following equation:
f(x)=a(x(1))(x0)(x2)=a[x(x+1)(x2)]
=a(x3x22x)
as it passes through (1,-6), we should have
a(131221)=6
or 2a=6 or a=3
Then function is f(x)=3(x3x22x)=3x33x26x

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