Which equation demonstrates the multiplicative identity property? A) (-3+5i)+0=-3+5i; B) (-3+5i)(1)=-3+5i; C) (-3+5i)(-3+5i)=-16-30i; D) (-3+5i)(3-5i)=16+30i

supermamanswtk

supermamanswtk

Answered question

2023-01-07

Which equation demonstrates the multiplicative identity property? A(-3+5i)+0=-3+5i B(-3+5i)(1)=-3+5i C(-3+5i)(-3+5i)=-16-30i D(-3+5i)(3-5i)=16+30i

Answer & Explanation

bolwoninghch

bolwoninghch

Beginner2023-01-08Added 11 answers

The ideal decision is B (-3+5i)(1)=-3+5i
Explanation For The Correct Option:
Option(B):
The given phrase
(-3+5i)(1)=-3+5i
We know a number x is called multiplicative identity if a,a·x=a
Since we obtain the same expression when we multiply 1 by itself, we can see that it is an identity element in this case.
Thus, this equation demonstrates the multiplicative identity property.
Explanation For incorrect Options:
Option(A):
The given expression
(-3+5i)+0=-3+5i
Here 0 is an additive identity.
Hence, the additive identity property of this equation is shown.
Thus, it is an incorrect option.
Option(C):
The given expression
(-3+5i)(-3+5i)=-16-30i
It is nothing but square of a complex number.
So, It doesn't demonstrate any identity.
Hence, it is an incorrect option.
Option(D):
The given expression
(-3+5i)(3-5i)=16+30i
Simply multiplying two complex numbers results in this.
So, It doesn't demonstrate any identity.
Therefore, it is an incorrect answer.
Hence, option B is the correct answer.

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