In a relay race,there are six teams A,B,C,D,E,F.(i)What is the probability that A,B,C,D finish first,...

Kason Wong

Kason Wong

Answered

2022-12-27

In a relay race,there are six teams A,B,C,D,E,F.(i)What is the probability that A,B,C,D finish first, second, third and fourth respectively.(ii)What is the probability that A,B,C and D are first four to finish(in any order).Assume that all finishing orders are equally likely.

Answer & Explanation

Toparellon12

Toparellon12

Expert

2022-12-28Added 6 answers

Here there are 6 teams .
Out of this only 4 teams wins.
ie
total number of orders= 6P4=360
n(S)= 360
(1) There is only one way ABCD could be in sequence,
ie n(L) = 1
there for probability of A,B,C,D finish first, second, third and fourth respectively= n(S)/n(L)
= 1/360
(2) probability that A,B,C and D are first four to finish
Let's create a sample set for this
M= ABCD, ABDC,ACBD,ACDB,ADBC,ADCB,
There are six possible outcomes here with A as the first letter. Simillarly with BCD there are 6 outcomes each,
total number of such outcomes= 6*4=24
therefor probability that A,B,C and D are first four to finish = 24/360
=1/15

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get your answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?