nonhumanWd3

2022-12-05

Solve $5{x}^{2}-2x-3$

Bryson Carlson

Expert

${a}^{2}+bx+c=0\phantom{\rule{0ex}{0ex}}D={b}^{2}-4ac$
if D>0 then roots are real and distinct
if D=0 then roots are real and equal
if D<0 then roots are non real or imaginary
${5}^{2}-2x-3=0\phantom{\rule{0ex}{0ex}}D=\left(-4{\right)}^{2}-4×5×\left(-3\right)$
Here, D>0, then roots will be real and distinct

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