Write an equation of the line that passes through the point (2,-1) and is perpendicular to the line 2x−3y = 5

Meldeaktezl

Meldeaktezl

Answered question

2022-09-06

Write an equation of the line that passes through the point (2,-1) and is perpendicular to the line 2 x 3 y = 5

Answer & Explanation

Caiden Brewer

Caiden Brewer

Beginner2022-09-07Added 5 answers

Given that,
Point (2,-1)
Perpendicular line equation is 2x-3y=5
3 y = 2 x 5 y = 2 3 x 5 3
so, slope = m 1 = 2 3
Two lines are prependicilar then
m 1 × m 2 = 1 2 3 × m 1 = 1 m 2 = 3 2
The equation of line passes through ( x 1 , y 1 ) and slope m is y y 1 = m ( x x 1 )
Here, the equation of line passes through (2,-1) and m = m 2 = 3 2 is
y ( 1 ) = 3 2 ( x 2 ) y + 1 = 3 2 x + 6 2 y = 3 2 x + 3 1 y = 3 2 x + 2

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