Use the given conditions to write an equation for the line in point-slope form and general form. Passing through (-3,6) and parallel to the line whose equation is 8x-9y-5=0 1. The equation of the line in point-slope form is ... (Type an equation. Use integers or fractions for any numbers in the equation) 2. Choose the correct equation of the line in general form a. 8x-9y=78 b. 8x-9y=78 c. 9x-8y=78 d. 9y-8x=-78

themediamafia73

themediamafia73

Answered question

2022-09-05

Use the given conditions to write an equation for the line in point-slope form and general form. Passing through (-3,6) and parallel to the line whose equation is 8x-9y-5=0
1. The equation of the line in point-slope form is ...
(Type an equation. Use integers or fractions for any numbers in the equation)
2. Choose the correct equation of the line in general form
a. 8x-9y=78
b. 8x-9y=78
c. 9x-8y=78
d. 9y-8x=-78

Answer & Explanation

Willie Gilmore

Willie Gilmore

Beginner2022-09-06Added 8 answers

The equation of the parallel line in standard form is: 8x - 9y = 5 making the slope 8/9. (-A/B)
The equation of the line in question in point slope form would be: y - 6 = 8/9(x + 3)
Convert to standard form by:
1. Distributing. y - 6 = 8/9 x + 8/3
2. Multiply by common denominator. 9y - 54 = 8x + 24
3. Move 8x to left side and -54 to the right side with opposite operations. -8x + 9y = 78
4. Multiply by -1 to make the leading coefficient a positive integer. 8x - 9y = -78

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