A car is driving a distance of 10 miles. The chart below gives the distance the car has traveled at several times during the trip. Calculate the average rate of change between each successive pair of times. What is the common name for this value? Time (min)0 5 8 12 18 20 Distance (miles) 0 2 4 6 8 10

Quessyrutty6w

Quessyrutty6w

Answered question

2022-07-29

A car is driving a distance of 10 miles. The chart below gives the distance the car has traveled at several times during the trip. Calculate the average rate of change between each successive pair of times. What is the common name for this value?
Time (min)0 5 8 12 18 20
Distance (miles) 0 2 4 6 8 10

Answer & Explanation

Jorge Franklin

Jorge Franklin

Beginner2022-07-30Added 11 answers

(0,5) :
We just do (difference in distance)/(difference in time)
= (2 - 0) / (5 - 0)
2/5 miles/min
= 0.4 miles/min

(5,8) :
(4-2)/(8-5)
= 2/3 miles/min

(8,12) :
= (6-4)/(12-8)
= 2/4
= 0.5 miles/min

(12,18):
= (8-6)/(18-12)
= 2/6
= 1/3 miles/min

(18,20) :
= (10-8)/(20-18)
= 2/2
= 1 mile/min
These are the average rates...
The common name is "average velocity"

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