Carpanedam7

2022-07-28

Factor the cubic polynomial $P\left(x\right)={x}^{3}-7x+6$. Use your factorization tond the roots of P.

cindysnifflesuz

Expert

putting x=1 we get p(1)=1-7+6= 0
so; x=1 is one of the root
so; our function changes to $\left(x-1\right)\left({x}^{2}+x-6\right)=\left(x-1\right)\left(x-2\right)\left(x+3\right)$
so; the roots are 1 , 2 and -3

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