The price p and the quantity x sold of a certain product obey the demand equation: P=-1/8X+100, {X/0 </ X </ 800} What is the revenue, R(x) = x . p(x) ,to the nearest dollar when 700 units are sold?

capellitad9

capellitad9

Answered question

2022-07-28

The price p and the quantity x sold of a certain product obey the demand equation: P=-1/8X+100, {X/0 </ X </ 800}
What is the revenue, R(x) = x . p(x) ,to the nearest dollar when 700 units are sold?

Answer & Explanation

wintern90

wintern90

Beginner2022-07-29Added 12 answers

P = 1 8 + 100
revenue = x p ( x ) = x 2 8 + 100 x
revenue when units sold = 700 is 700 2 8 + 100 × 700 = 8750

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