Simplifying fraction with square root as denominator I'm trying to find the integral of: <msty

skynugurq7

skynugurq7

Answered question

2022-07-13

Simplifying fraction with square root as denominator
I'm trying to find the integral of:
2 x 3 x + x 2 x
but I first need to simplify it so I tried dividing by the x for each of the numbers on the top like so:
2 x x
and did the same for the others. For the one above it was easy to see that it just simplifies to 2. But I am unsure how to do the same for the others for instance 3 x x I know to x but i don't know what 3 x x would come out with?

Answer & Explanation

Janiyah Patton

Janiyah Patton

Beginner2022-07-14Added 12 answers

HINT :
Rewrite
2 x 3 x + x 2 x = 2 x 3 x x + x x x = 2 x 3 x x + x x x x
or
2 x 3 x + x 2 x = 2 x 1 2 3 x 1 + x 2 x 1 2 ,
where x = x x and x = x 1 2
Ayaan Barr

Ayaan Barr

Beginner2022-07-15Added 6 answers

Hint:
2 x 3 x + x 2 x = 2 3 x + x 3 / 2

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