klipbodok6

2022-07-09

How do you write the inequality and solve given "three times a number increased by 8 is no more than the number decreased by 4"?

Asdrubali2r

Expert

Step 1
Let the number be a,
Three times a number increased by $8⇒3a+8$
Is no more than' means it can be the same as or less than the number decreased by 4 :
$3a+8\le a-4$
Step 2
Take the terms with variable a to left hand side and keep the other terms on right hand side. Apply transposition rules:
$3a-a\le -8-4$
$2a\le -12$
$a\le -6$

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